# Totally Disconnected but Connected Set must be Singleton

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## Theorem

Let $T = \left({S, \tau}\right)$ be a topological space.

Let $H \subseteq S$ be both totally disconnected and connected.

Then $H$ is a singleton.

## Proof

If $H$ is totally disconnected then its individual points are separated.

If $H$ is connected it can not be represented as the union of two (or more) separated sets.

So $H$ can have only one point in it.

$\blacksquare$

## Sources

- 1970: Lynn Arthur Steen and J. Arthur Seebach, Jr.:
*Counterexamples in Topology*... (previous) ... (next): $\text{I}: \ \S 4$: Disconnectedness