116
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Number
$116$ (one hundred and sixteen) is:
- $2^2 \times 29$
- The $2$nd term of the $2$nd $5$-tuple of consecutive integers have the property that they are not values of the divisor sum function $\map {\sigma_1} n$ for any $n$:
- $\tuple {115, 116, 117, 118, 119}$
- The $1$st of the $4$th pair of consecutive integers which both have $6$ divisors:
- $\map {\sigma_0} {116} = \map {\sigma_0} {117} = 6$
- The $9$th noncototient after $10$, $26$, $34$, $50$, $52$, $58$, $86$, $100$:
- $\nexists m \in \Z_{>0}: m - \map \phi m = 116$
- where $\map \phi m$ denotes the Euler $\phi$ function
- The $11$th integer $m$ such that $m! + 1$ (its factorial plus $1$) is prime:
- $0$, $1$, $2$, $3$, $11$, $27$, $37$, $41$, $73$, $77$, $116$
- The $22$nd positive integer $n$ such that no factorial of an integer can end with $n$ zeroes.
- The $54$th positive integer after $2$, $3$, $4$, $7$, $8$, $\ldots$, $95$, $96$, $100$, $101$, $102$, $107$, $112$ which cannot be expressed as the sum of distinct pentagonal numbers.
Also see
- Previous ... Next: Sequence of Integers whose Factorial plus 1 is Prime
- Previous ... Next: Pairs of Consecutive Integers with 6 Divisors
- Previous ... Next: Noncototient
- Previous ... Next: Numbers of Zeroes that Factorial does not end with
- Previous ... Next: Numbers not Expressible as Sum of Distinct Pentagonal Numbers
- Previous ... Next: Quintuplets of Consecutive Integers which are not Divisor Sum Values
Sources
- 1986: David Wells: Curious and Interesting Numbers ... (previous) ... (next): $116$