Congruence Modulo Equivalence for Integers in P-adic Integers
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Theorem
Let $\Z_p$ be the $p$-adic integers for some prime $p$.
For any $a, b \in \Z_p$ and $n \in \N$, let $x \equiv y \pmod{p^n \Z_p}$ denote congruence modulo the principal ideal $p^n\Z_p$.
For any integers $a, b \in \Z$ and $n \in \N$, let $x \equiv y \pmod{p^n}$ denote congruence modulo integer $p^n$.
Let $x, y \in \Z$ be integers.
Let $k \in \N_{>0}$.
The following statements are equivalent:
- $(1)\quad x \equiv y \pmod{p^k \Z_p}$
- $(2)\quad x \equiv y \pmod{p^k}$
- $(3)\quad p^k \divides \paren{x - y}$
Proof
Lemma
- $\forall a \in \Z: \dfrac a {p^k} \in \Z_p \iff \dfrac a {p^k} \in \Z$
$\Box$
We have:
\(\ds x\) | \(\equiv\) | \(\ds y \pmod{p^k\Z_p}\) | ||||||||||||
\(\ds \leadstoandfrom \ \ \) | \(\ds x - y\) | \(\in\) | \(\ds p^k\Z_p\) | Definition of Congruence Modulo an Ideal | ||||||||||
\(\ds \leadstoandfrom \ \ \) | \(\ds \exists z \in \Z_p: \, \) | \(\ds x - y\) | \(=\) | \(\ds p^kz\) | Definition of Principal Ideal | |||||||||
\(\ds \leadstoandfrom \ \ \) | \(\ds \dfrac {x - y} {p^k}\) | \(\in\) | \(\ds \Z_p\) | Divide both sides by $p^k$ | ||||||||||
\(\ds \leadstoandfrom \ \ \) | \(\ds \dfrac {x - y} {p^k}\) | \(\in\) | \(\ds \Z\) | Lemma | ||||||||||
\(\ds \leadstoandfrom \ \ \) | \(\ds \exists a \in \Z: \, \) | \(\ds \dfrac {x - y} {p^k}\) | \(=\) | \(\ds a\) | ||||||||||
\(\ds \leadstoandfrom \ \ \) | \(\ds \exists a \in \Z: \, \) | \(\ds x - y\) | \(=\) | \(\ds p^ka\) | Multiply both sides by $p^k$ | |||||||||
\(\ds \leadstoandfrom \ \ \) | \(\ds p^k\) | \(\divides\) | \(\ds \paren{x - y}\) | Definition of Divisor of Integer | ||||||||||
\(\ds \leadstoandfrom \ \ \) | \(\ds x\) | \(\equiv\) | \(\ds y \pmod{p^k}\) | Definition of Congruence Modulo Integer |
$\blacksquare$