Connected iff no Proper Clopen Sets
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Theorem
Let $T = \struct {S, \tau}$ be a topological space.
Then:
- $T$ is connected
- there exists no non-empty proper subset of $S$ which is clopen in $T$.
Proof
Sufficient Condition
Let $T$ be connected.
Aiming for a contradiction, suppose there exists $H \subset S$ such that:
- $H$ is clopen in $T$
- $H$ is a non-empty proper subset of $S$, that is:
- $\O \ne H \ne S$
Then $H$ and $\relcomp S H$ are open sets whose union is $S$.
Thus $\set {H \mid \relcomp S H}$ form a partition of $S$.
Hence by definition, $T$ is not connected.
This contradicts our assumption.
Hence, by Proof by Contradiction, such $H$ does not exist.
$\Box$
Necessary Condition
Let there exist no non-empty proper subset of $S$ which is clopen in $T$.
Aiming for a contradiction, suppose $T$ is not connected (disconnected).
By definition, there is a partition $\set {A \mid B}$ of $S$.
Then $\relcomp S A = B$ is open.
Hence by definition $A$ is closed.
Thus $A$ is clopen such that:
- $\O \ne A \ne S$
But then by definition $A$ is a non-empty proper subset of $S$ which is clopen in $T$.
This contradicts our assumption.
Hence, by Proof by Contradiction, $T$ is connected.
$\blacksquare$