Convergent Complex Series/Examples/1 over n^2 - i n

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Example of Convergent Complex Series

The series $\ds \sum_{n \mathop = 1}^\infty a_n$, where:

$a_n = \dfrac 1 {n^2 - i n}$

is convergent.


Proof

\(\ds \sum_{n \mathop = 1}^\infty \cmod {\dfrac 1 {n^2 - i n} }\) \(=\) \(\ds \sum_{n \mathop = 1}^\infty \cmod {\dfrac {n^2 + i n} {\paren {n^2 - i n} \paren {n^2 + i n} } }\)
\(\ds \) \(=\) \(\ds \sum_{n \mathop = 1}^\infty \cmod {\dfrac {n^2 + i n} {n^4 + n^2} }\)
\(\ds \) \(\le\) \(\ds \sum_{n \mathop = 1}^\infty \cmod {\dfrac {n^2 + i n} {n^4} }\)
\(\ds \) \(=\) \(\ds \sum_{n \mathop = 1}^\infty \cmod {\dfrac {n + i} {n^3} }\)
\(\ds \) \(\le\) \(\ds \sum_{n \mathop = 1}^\infty \dfrac 2 {n^2}\)

Thus $\ds \sum_{n \mathop = 1}^\infty \dfrac 1 {n^2 - i n}$ is absolutely convergent.

The result follows from Absolutely Convergent Series is Convergent: Complex Numbers.

$\blacksquare$


Sources