Convergent Real Sequence is Bounded/Proof 1
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Theorem
Let $\sequence {x_n}$ be a sequence in $\R$.
Let $l \in A$ such that $\ds \lim_{n \mathop \to \infty} x_n = l$.
Then $\sequence {x_n}$ is bounded.
Proof
From Real Number Line is Metric Space, the set $\R$ under the usual metric is a metric space.
By Convergent Sequence in Metric Space is Bounded it follows that:
- $\exists M > 0: \forall n, m \in \N: \size {x_n - x_m} \le M$
Then for $n \in \N$, by the Triangle Inequality for Real Numbers:
\(\ds \size {x_n}\) | \(=\) | \(\ds \size {x_n - x_1 + x_1}\) | ||||||||||||
\(\ds \) | \(\le\) | \(\ds \size {x_n - x_1} + \size {x_1}\) | ||||||||||||
\(\ds \) | \(\le\) | \(\ds M + \size {x_1}\) |
Hence $\sequence {x_n}$ is bounded.
$\blacksquare$