Group Action defines Permutation Representation
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Theorem
Let $\map \Gamma X$ be the set of permutations on a set $X$.
Let $G$ be a group.
Let $\phi: G \times X \to X$ be a group action.
For $g \in G$, let $\phi_g: X \to X$ be the mapping defined as:
- $\map {\phi_g} x = \map \phi {g, x}$
Let $\tilde \phi: G \to \map \Gamma X$ be the permutation representation associated to $\phi$, defined by:
- $\map {\tilde \phi} g := \phi_g$
Then $\tilde \phi$ is a group homomorphism.
Proof
From Group Action determines Bijection:
- $\phi_g \in \map \Gamma X$
for $g \in G$.
Let $g, h \in G$.
Recall the definition of Group Action:
- $\forall \tuple {g, x} \in G \times X: \map \phi {g, x} \in X = g \wedge x \in X$
First we show that for all $x \in X$:
- $\map {\phi_g \circ \phi_h} x = \map {\phi_{g h} } x$
Thus:
\(\ds \map {\phi_g \circ \phi_h} x\) | \(=\) | \(\ds g \wedge \paren {h \wedge x}\) | Definition of $\phi_g$, $\phi_h$ | |||||||||||
\(\ds \) | \(=\) | \(\ds \paren {g h} \wedge x\) | Definition of Group Action | |||||||||||
\(\ds \) | \(=\) | \(\ds \map {\phi_{g h} } x\) | Definition of $\phi_{g h}$ |
Also, we have:
- $e \wedge x = x \implies \map {\phi_e} x = x$
where $e$ is the identity of $G$.
Therefore, we have shown that $\tilde \phi: G \to \map \Gamma X: g \mapsto \phi_g$ is a group homomorphism.
$\blacksquare$
Sources
- 1982: P.M. Cohn: Algebra Volume 1 (2nd ed.) ... (previous) ... (next): $\S 3.3$: Group actions and coset decompositions