Intersection with Empty Set

From ProofWiki
Jump to navigation Jump to search

Theorem

The intersection of any set with the empty set is itself the empty set:

$S \cap \O = \O$


Proof

\(\ds S \cap \O\) \(\subseteq\) \(\ds \O\) Intersection is Subset
\(\ds \O\) \(\subseteq\) \(\ds S \cap \O\) Empty Set is Subset of All Sets
\(\ds \leadsto \ \ \) \(\ds S \cap \O\) \(=\) \(\ds \O\) Definition 2 of Set Equality

$\blacksquare$


Also see


Sources