Matrix Space is Module

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Theorem

Let $\struct {R, +, \circ}$ be a ring.

Let $\mathbf A = \sqbrk a_{m n}$ be an $m \times n$ matrix over $\struct {R, +, \circ}$.


Then the matrix space $\map {\MM_R} {m, n}$ of all $m \times n$ matrices over $R$ is a module.


Proof

This follows as $\map {\MM_R} {m, n}$ is a direct instance of the module given in the module of all mappings, where $\map {\MM_R} {m, n}$ is the $R$-module $R^{\closedint 1 m \times \closedint 1 n}$.

The $S$ of that example is the set $\closedint 1 m \times \closedint 1 n$, while the $G$ of that example is the $R$-module $R$.


Let $\sqbrk a_{i j}$ and $\sqbrk b_{i j}$ be the $\tuple{i, j}$th element of $m \times n$ matrices $\mathbf A$ and $\mathbf B$ respectively.

Let $\lambda$ and $\mu$ be arbitrary elements of $R$.


We have for all $i \in \closedint 1 m$, $j \in \closedint 1 n$, by egregious abuse of notation:

\(\ds \lambda \circ \paren {\mathbf A + \mathbf B}\) \(=\) \(\ds \lambda \circ \paren {a_{i j} + b_{i j} }\) Definition of Matrix Entrywise Addition over Ring
\(\ds \) \(=\) \(\ds \lambda \circ a_{i j} + \lambda \circ b_{i j}\) Ring Axiom $\text D$: Distributivity of Product over Addition
\(\ds \) \(=\) \(\ds \lambda \circ \mathbf A + \lambda \circ \mathbf B\) hence fulfilling Module Axiom $\text M 1$: Distributivity over Module Addition


\(\ds \paren {\lambda + \mu} \circ \mathbf A\) \(=\) \(\ds \paren {\lambda + \mu} \circ a_{i j}\) Definition of Matrix Scalar Product over Ring
\(\ds \) \(=\) \(\ds \lambda \circ a_{i j} + \mu \circ a_{i j}\) Ring Axiom $\text D$: Distributivity of Product over Addition
\(\ds \) \(=\) \(\ds \lambda \circ \mathbf A + \mu \circ \mathbf A\) hence fulfilling Module Axiom $\text M 2$: Distributivity over Scalar Addition


\(\ds \paren {\lambda \circ \mu} \circ \mathbf A\) \(=\) \(\ds \paren {\lambda \circ \mu} \circ a_{i j}\) Definition of Matrix Scalar Product over Ring
\(\ds \) \(=\) \(\ds \lambda \circ \paren {\mu \circ a_{i j} }\) Ring Axiom $\text M1$: Associativity of Product
\(\ds \) \(=\) \(\ds \lambda \circ \paren {\mu \circ \mathbf A}\) hence fulfilling Module Axiom $\text M 3$: Associativity

$\blacksquare$


Sources