Ordinal Multiplication via Cantor Normal Form/Limit Base
Theorem
Let $x$ and $y$ be ordinals.
Let $x$ be a limit ordinal.
Let $y > 0$.
Let $\sequence {a_i}$ be a sequence of ordinals that is strictly decreasing on $1 \le i \le n$.
Let $\sequence {b_i}$ be a sequence of finite ordinals.
Then:
- $\ds \sum_{i \mathop = 1}^n \paren {x^{a_i} b_i} \times x^y = x^{a_1 \mathop + y}$
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Proof
The proof shall proceed by finite induction on $n$:
For all $n \in \N_{\le 0}$, let $\map P n$ be the proposition:
- $\ds \sum_{i \mathop = 1}^n \paren {x^{a_i} b_i} \times x^y = x^{a_1 \mathop + y}$
Since $x$ is a limit ordinal, it follows that $x^y$ is a limit ordinal by Limit Ordinals Closed under Ordinal Exponentiation.
Basis for the Induction
$\map P 1$ is the statement:
- $\ds \sum_{i \mathop = 1}^1 \paren {x^{a_i} b_i} \times x^y = x^{a_1 \mathop + y}$
\(\ds \sum_{i \mathop = 1}^1 \paren {x^{a_i} b_i} \times x^y\) | \(=\) | \(\ds \paren {x^{a_i} \times b_i} \times x^y\) | Definition of Ordinal Sum | |||||||||||
\(\ds \) | \(=\) | \(\ds x^{a_i} \times \paren {b_i \times x^y}\) | Ordinal Multiplication is Associative | |||||||||||
\(\ds \) | \(=\) | \(\ds x^{a_i} \times x^y\) | Finite Ordinal Times Ordinal | |||||||||||
\(\ds \) | \(=\) | \(\ds x^{a_i \mathop + y}\) | Ordinal Sum of Powers |
This is our basis for the induction.
$\Box$
Induction Hypothesis
Now we need to show that, if $\map P k$ is true, where $k \ge 1$, then it logically follows that $\map P {k + 1}$ is true.
So this is our induction hypothesis:
- $\ds \sum_{i \mathop = 1}^k \paren {x^{a_i} b_i} \times x^y = x^{a_1 + y}$
Then we need to show:
- $\ds \sum_{i \mathop = 1}^{k \mathop + 1} \paren {x^{a_i} b_i} \times x^y = x^{a_1 \mathop + y}$
Induction Step
This is our induction step:
By Upper Bound of Ordinal Sum, it follows that:
- $\ds \sum_{i \mathop = 1}^n \paren {x^{a_{i \mathop + 1} } b_{i \mathop + 1} } < x^{a_1}$
By Membership is Left Compatible with Ordinal Multiplication:
\(\ds x^{a_1} b_1\) | \(\le\) | \(\ds x^{a_1} b_1 + \sum_{i \mathop = 1}^k \paren {x^{a_{i \mathop + 1} } b_{i \mathop + 1} }\) | Ordinal is Less than Sum | |||||||||||
\(\ds \) | \(\le\) | \(\ds x^{a_1} b_1 + x^{a_1}\) | Membership is Left Compatible with Ordinal Addition | |||||||||||
\(\ds \leadsto \ \ \) | \(\ds x^{a_1} \times b_1 \times x^y\) | \(\le\) | \(\ds \sum_{i \mathop = 1}^{k \mathop + 1} \paren {x^{a_i} b_i} \times x^y\) | Subset is Right Compatible with Ordinal Multiplication and General Associative Law for Ordinal Sum | ||||||||||
\(\ds \) | \(\le\) | \(\ds x^{a_1} \times \paren {b_1 + 1} \times x^y\) | Subset is Right Compatible with Ordinal Multiplication |
But:
\(\ds x^{a_1} \times b_1 \times x^y\) | \(=\) | \(\ds x^{a_1} \times x^y\) | Finite Ordinal Times Ordinal | |||||||||||
\(\ds \) | \(=\) | \(\ds x^{a_1 \mathop + y}\) | Ordinal Sum of Powers | |||||||||||
\(\ds x^{a_1} \times \paren {b_1 + 1} \times x^y\) | \(=\) | \(\ds x^{a_1} \times x^y\) | Finite Ordinal Times Ordinal | |||||||||||
\(\ds \) | \(=\) | \(\ds x^{a_1 \mathop + y}\) | Ordinal Sum of Powers |
Therefore:
\(\ds x^{a_1 \mathop + y}\) | \(\le\) | \(\ds \sum_{i \mathop = 1}^n \paren {x^{a_i} b_i} \times x^y\) | Substitutivity of Class Equality | |||||||||||
\(\ds \) | \(\le\) | \(\ds x^{a_1 \mathop + y}\) | Substitutivity of Class Equality | |||||||||||
\(\ds \leadsto \ \ \) | \(\ds \sum_{i \mathop = 1}^n \paren {x^{a_i} b_i} \times x^y\) | \(=\) | \(\ds x^{a_1 \mathop + y}\) | Definition 2 of Set Equality |
$\blacksquare$
Also see
Sources
- 1971: Gaisi Takeuti and Wilson M. Zaring: Introduction to Axiomatic Set Theory: $\S 8.46$