# Solution of Constant Coefficient LSOODE

## Proof Technique

Consider the linear second order ODE with constant coefficients:

$(1): \quad \dfrac {\d^2 y} {\d x^2} + p \dfrac {\d y} {\d x} + q y = \map R x$

where $p$ and $q$ are constants and $\map R x$ is a function of $x$.

The general solution to $(1)$ can be found as follows.

Find the roots $m_1$ and $m_2$ of the auxiliary equation $m^2 + p m + q = 0$

Hence the general solution $\map {y_g} x$ is found of the homogeneous linear second order ODE:

$(2): \quad \dfrac {\d^2 y} {\d x^2} + p \dfrac {\d y} {\d x} + q y = 0$

Select a trial solution

Using the Method of Undetermined Coefficients, identify a trial solution to $(1)$ by selecting a real function $\map f x$ of the same form as $\map R x$.

This can be done when $\map R x$ is in the form:

a polynomial in $x$:
$\da \map R x = \sum_{j \mathop = 0}^n a_j x^j$
of the form $K e^{a x}$
of the form $A \cos a x + B \sin b x$

or a sum or product of these.

Solve the trial solution

Differentiate $f$ twice with respect to $x$.

Then substitute for $y$, $y'$ and $y''$ in $(1)$ to obtain a system of simultaneous equations from which the so far undetermined coefficients of $f$ can be evaluated.

Hence a particular solution $y_p$ to $(1)$ is obtained.

Other cases

In the cases when $\map R x$ is not of one of the above forms, $(1)$ can be split into its factors as follows.

Express $(1)$ in the form $\paren {D^2 + p D + q} y = \map R x$
Express it further in the form $\paren {D + m_1} \paren {D + m_2} y = \map R x$
Solve the resulting linear first Order ODE with constant coefficients.

The general solution to $(1)$ is then:

$\map y x = \map {y_g} x + \map {y_p} x$

$\blacksquare$