Subfield Test/Three-Step
Theorem
Let $\struct {F, +, \times}$ be a field whose zero is $0_F$.
Let $K$ be a subset of $F$.
$\struct {K, +, \times}$ is a subfield of $\struct {F, +, \times}$ if and only if these all hold:
- $(1): \quad K^* \ne \O$
- $(2): \quad \forall x, y \in K: x - y \in K$
- $(3): \quad \forall x \in K: \forall y \in K^*: \dfrac x y \in K$
where $K^*$ denotes $K \setminus \set {0_F}$.
Proof
Necessary Condition
Let $\struct {K, +, \times}$ be a subfield of $\struct {F, +, \times}$.
Then the conditions $(1)$ to $(3)$ all hold by virtue of the field axioms.
$\Box$
Sufficient Condition
Suppose the conditions $(1)$ to $(3)$ hold.
As $K^* \ne \O$, it follows that $K \ne \O$.
From the One-Step Subgroup Test, it follows that $\struct {K, +}$ is a subgroup of $\struct {F, +}$.
Also from the One-Step Subgroup Test, it follows that $\struct {K^*, \times}$ is a subgroup of $\struct {F^*, \times}$.
As $\struct {F, +, \times}$ is a field, then $\times$ is commutative on all of $F$.
From Restriction of Commutative Operation is Commutative, $\times$ is commutative also on $K$.
As $\struct {F, +, \times}$ is a field, then $\times$ is distributive over $+$ on all of $F$.
From Restriction of Operation Distributivity $\times$ is distributive over $+$ also on $K$.
Thus $\struct {K, +, \times}$ is a field.
$\blacksquare$
Sources
- 1971: Allan Clark: Elements of Abstract Algebra ... (previous) ... (next): Chapter $3$: Field Theory: Definition and Examples of Field Structure: $\S 88 \alpha$
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- 1969: C.R.J. Clapham: Introduction to Abstract Algebra ... (previous) ... (next): Chapter $4$: Fields: $\S 16$. Subfields: Theorem $26$