# Cauchy-Bunyakovsky-Schwarz Inequality

(Redirected from Cauchy-Schwarz Inequality)

## Theorem

### Semi-Inner Product Spaces

Let $\mathbb K$ be a subfield of $\C$.

Let $V$ be a semi-inner product space over $\mathbb K$.

Let $x, y$ be vectors in $V$.

Then:

$\size {\innerprod x y}^2 \le \innerprod x x \innerprod y y$

### Lebesgue $2$-Space

Let $\struct {X, \Sigma, \mu}$ be a measure space.

Let $f, g: X \to \R$ be $\mu$-square integrable functions, that is $f, g \in \map {\LL^2} \mu$, Lebesgue $2$-space.

Then:

$\ds \int \size {f g} \rd \mu \le \norm f_2^2 \cdot \norm g_2^2$

where $\norm {\, \cdot \,}_2$ is the $2$-norm.

### Cauchy's Inequality

The special case of the Cauchy-Bunyakovsky-Schwarz Inequality in a Euclidean space is called Cauchy's Inequality.

It was Cauchy who first published this result in $1821$.

It is usually stated as:

$\ds \sum {r_i^2} \sum {s_i^2} \ge \paren {\sum {r_i s_i} }^2$

### Complex Numbers

$\displaystyle \paren {\sum \cmod {w_i}^2} \paren {\sum \cmod {z_i}^2} \ge \cmod {\sum w_i z_i}^2$

where all of $w_i, z_i \in \C$.

### Definite Integrals

Let $f$ and $g$ be real functions which are continuous on the closed interval $\closedint a b$.

Then:

$\ds \paren {\int_a^b \map f t \, \map g t \rd t}^2 \le \int_a^b \paren {\map f t}^2 \rd t \int_a^b \paren {\map g t}^2 \rd t$

## Also known as

This theorem is also known as the Cauchy-Schwarz inequality or just the Schwarz inequality.

## Source of Name

This entry was named for Augustin Louis CauchyKarl Hermann Amandus Schwarz and Viktor Yakovlevich Bunyakovsky.