Dynkin System Closed under Intersections is Sigma-Algebra
Theorem
Let $X$ be a set, and let $\DD$ be a Dynkin system on $X$.
Suppose that $\DD$ satisfies the following condition:
- $(1):\quad \forall D, E \in \DD: D \cap E \in \DD$
That is, $\DD$ is closed under intersection.
Then $\DD$ is a $\sigma$-algebra.
Proof
The first two conditions for a Dynkin system are identical to those for a $\sigma$-algebra.
Hence it is only required to verify that $(1)$ implies that $\DD$ is closed under arbitrary countable unions.
So let $\sequence {D_n}_{n \mathop \in \N}$ be a sequence in $\DD$.
Now define the sequence $\sequence {E_n}_{n \mathop \in \N}$ by:
- $\ds E_n := D_n \cap \paren {X \setminus \bigcup_{m \mathop < n} D_m}$
By Dynkin System Closed under Union and $(1)$, it follows that $E_n \in \DD$ for all $n \in \N$.
Lemma
For all $n \in \N$, it holds that:
- $\ds \bigcup_{k \mathop = 0}^n E_k = \bigcup_{k \mathop = 0}^n D_k$
Proof of Lemma
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The lemma, combined with the definition of the $E_n$, gives immediately that for all $n \in \N$:
- $\ds E_n \in X \setminus \bigcup_{m \mathop < n} D_m = X \setminus \bigcup_{m \mathop < n} E_m$
whence the $E_n$ are pairwise disjoint.
Another consequence is that:
- $\ds \bigcup_{n \mathop \in \N} D_n = \bigcup_{n \mathop \in \N} E_n$
Now since the $E_n$ are pairwise disjoint, it follows that:
- $\ds \bigcup_{n \mathop \in \N} E_n \in \DD$
which, combined with above equality, concludes in:
- $\ds \bigcup_{n \mathop \in \N} D_n \in \DD$
Therefore, $\DD$ is closed under countable unions, making it a $\sigma$-algebra.
$\blacksquare$
Sources
- 2005: René L. Schilling: Measures, Integrals and Martingales ... (previous) ... (next): $5.4$