Euclid's Lemma for Prime Divisors/Proof 3
Jump to navigation
Jump to search
Lemma
Let $p$ be a prime number.
Let $a$ and $b$ be integers such that:
- $p \divides a b$
where $\divides$ means is a divisor of.
Then $p \divides a$ or $p \divides b$.
In the words of Euclid:
- If two numbers by multiplying one another make some number, and any prime number measure the product, it will also measure one of the original numbers.
(The Elements: Book $\text{VII}$: Proposition $30$)
Proof
Let $p \divides a b$.
Suppose $p \nmid a$.
Then by Proposition $29$ of Book $\text{VII} $: Prime not Divisor implies Coprime:
- $p \perp a$
As $p \divides a b$, it follows by definition of divisor:
- $\exists e \in \Z: e p = a b$
So by Proposition $19$ of Book $\text{VII} $: Relation of Ratios to Products‎:
- $p : a = b : e$
But as $p \perp a$, by:
and:
it follows that:
- $p \divides b$
Similarly, if $p \perp b$ then $p \divides a$.
Hence the result.
$\blacksquare$
Historical Note
This proof is Proposition $30$ of Book $\text{VII}$ of Euclid's The Elements.
Sources
- 1926: Sir Thomas L. Heath: Euclid: The Thirteen Books of The Elements: Volume 2 (2nd ed.) ... (previous) ... (next): Book $\text{VII}$. Propositions
- 1992: George F. Simmons: Calculus Gems ... (previous) ... (next): Chapter $\text {A}.4$: Euclid (flourished ca. $300$ B.C.)
- 2008: Ian Stewart: Taming the Infinite ... (previous) ... (next): Chapter $7$: Patterns in Numbers: Euclid