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21 April 2024
| m 15:42 | Definition:Mapping diffhist +99 Prime.mover talk contribs | ||||
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15:40 | Definition:Inverse Mapping 4 changes history +697 [Prime.mover (4×)] | |||
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15:40 (cur | prev) +115 Prime.mover talk contribs | ||||
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10:01 (cur | prev) 0 Prime.mover talk contribs | ||||
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09:50 (cur | prev) +46 Prime.mover talk contribs | ||||
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09:47 (cur | prev) +536 Prime.mover talk contribs | ||||
| 10:14 | Image of Element under Inverse Mapping/Corollary 2 diffhist 0 Prime.mover talk contribs | ||||
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N 10:09 | Image of Element under Inverse Mapping/Corollary 1 3 changes history +1,417 [Prime.mover (3×)] | |||
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10:09 (cur | prev) +1 Prime.mover talk contribs | |||
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10:08 (cur | prev) +1,352 Prime.mover talk contribs (Removed redirect to Image of Element under Inverse Mapping/Corollary 2) Tag: Removed redirect | ||||
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10:00 (cur | prev) +1,299 Prime.mover talk contribs (Created page with "== Theorem == Let $S$ and $T$ be sets. Let $f: S \to T$ be a mapping such that its inverse $f^{-1}: T \to S$ is also a mapping. Then: <onlyinclude> :$\forall y \in T: \map f {\map {f^{-1} } y} = y$ </onlyinclude> == Proof == {{begin-eqn}} {{eqn | q = \forall x \in S, y \in T | l = \map f x | r = y | c = }} {{eqn | lo= \iff | l = \map {f^{-1} }...") | |||
| 10:01 | Move log Prime.mover talk contribs moved page Image of Element under Inverse Mapping/Corollary 1 to Image of Element under Inverse Mapping/Corollary 2 | ||||
| 09:49 | Definition:Inverse of Mapping diffhist +36 Prime.mover talk contribs | ||||