Definition:Preimage of Subset under Mapping/Definition 1

From ProofWiki
Jump to navigation Jump to search

Definition

Let $f: S \to T$ be a mapping.

Let $f^{-1} \subseteq T \times S$ be the inverse of $f$, defined as:

$f^{-1} = \set {\tuple {t, s}: \map f s = t}$

Let $Y \subseteq T$.


The preimage of $Y$ under $f$ is defined as:

$f^{-1} \sqbrk Y := \set {s \in S: \exists t \in Y: \map f s = t}$


That is, the preimage of $Y$ under $f$ is the image of $Y$ under $f^{-1}$, where $f^{-1}$ can be considered as a relation.


If no element of $Y$ has a preimage, then $f^{-1} \sqbrk Y = \O$.


Also known as

Some sources use counter image or inverse image instead of preimage.

Some sources hyphenate: pre-image.

Some sources use the notation $\map {f^\gets} Y$ for $f^{-1} \sqbrk Y$.


Also see


Sources

Retrieved from "https://proofwiki.org/w/index.php?title=Definition:Preimage_of_Subset_under_Mapping/Definition_1&oldid=680884"